-2x^2-24x=40

Solution for -2x^2-24x=40 equation:

-2x^2-24x=40

We move all terms to the left:

-2x^2-24x-(40)=0

a = -2; b = -24; c = -40;
Δ = b2-4ac
Δ = -242-4·(-2)·(-40)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16}{2*-2}=\frac{8}{-4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16}{2*-2}=\frac{40}{-4}
=-10
$